4x^2+40x^2+100x=0

Solution for 4x^2+40x^2+100x=0 equation:

4x^2+40x^2+100x=0

We add all the numbers together, and all the variables

44x^2+100x=0

a = 44; b = 100; c = 0;
Δ = b2-4ac
Δ = 1002-4·44·0
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10000}=100$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-100}{2*44}=\frac{-200}{88}
=-2+3/11
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+100}{2*44}=\frac{0}{88}
=0
$